Phenol (C_6H_6O) xrightarrow{Br_2 text{ in } | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) $1$. When phenol reacts with $Br_2$ in a non-polar solvent like $CS_2$ or $CHCl_3$ at low temperature,the reaction is monobromination. The major p

Vedclass · Accepted Answer

Vedclass · Answer

(D) $1$. When phenol reacts with $Br_2$ in a non-polar solvent like $CS_2$ or $CHCl_3$ at low temperature,the reaction is monobromination. The major product is $p$-bromophenol due to less steric hindrance compared to $o$-bromophenol. Thus,$X$ is $p$-bromophenol.$2$. When phenol reacts with $Br_2$ in water $(H_2O)$,the phenol ionizes to form the phenoxide ion,which is highly activating. This leads to rapid electrophilic substitution at all ortho and para positions,resulting in the formation of $2,4,6$-tribromophenol as the major product. Thus,$Y$ is $2,4,6$-tribromophenol.

Phenol $(C_6H_6O)$ $\xrightarrow{Br_2 \text{ in } CS_2}$ $X$ (Major product)
Phenol $(C_6H_6O)$ $\xrightarrow{Br_2 \text{ in } H_2O}$ $Y$ (Major product)
What are $X$ and $Y$ in the above reaction respectively?

Similar Questions

In the Liebermann nitroso reaction,what is the sequence of color changes observed in phenol?

Out of $o-$nitrophenol and $o-$cresol,which is more acidic?

$A$ compound $A$ $(C_{7}H_{8}O)$ is insoluble in $NaHCO_{3}$ solution but dissolves in $NaOH$ and gives a characteristic colour with neutral $FeCl_{3}$ solution. When treated with bromine water,compound $A$ forms the compound $B$ with the formula $C_{7}H_{5}OBr_{3}$. $A$ is:

What are $X$ and $Y$ respectively in the following set of reactions?

The correct options for the products $A$ and $B$ of the following reactions are:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Phenol $(C_6H_6O)$ $\xrightarrow{Br_2 \text{ in } CS_2}$ $X$ (Major product)Phenol $(C_6H_6O)$ $\xrightarrow{Br_2 \text{ in } H_2O}$ $Y$ (Major product)What are $X$ and $Y$ in the above reaction respectively?