Phenol on oxidation in air gives

The reactant is $4-hydroxy-3-methylbenzenesulfonic acid$. The reaction with $Br_2$ in $H_2O$ (bromine water) is an electrophilic aromatic substitution. The $-OH$ group is strongly activating and ortho/para directing. The $-SO_3H$ group is a good leaving group in the presence of excess bromine water. Predict the product of the reaction: $\xrightarrow{Br_2, H_2O} \text{Product}$

Among $I, II, III$ (Phenol,o-nitrophenol,and p-nitrophenol respectively),the boiling point follows the order:

What is the major product formed when phenol reacts with sodium hydroxide and carbon dioxide?

Match List-$I$ with List-$II$.

List-$I$ (Reactants)	List-$II$ (Products)
$A$. Phenol,$Zn / \Delta$	$I$. Salicylaldehyde
$B$. Phenol,$CHCl_3, NaOH, HCl$	$II$. Salicylic acid
$C$. Phenol,$CO_2, NaOH, HCl$	$III$. Benzene
$D$. Phenol,Conc. $HNO_3$	$IV$. Picric acid

Which one of the following is most reactive towards electrophilic attack?