Photo cells convert

$A$ photocell stops emission if it is maintained at $2V$ negative potential. The energy of the most energetic photoelectron is:

The quantum nature of light is explained by which of the following phenomena?

The following graph represents the variation of photocurrent with anode potential for a metal surface. Here $I_{1}, I_{2}$ and $I_{3}$ represent intensities and $\gamma_{1}, \gamma_{2}, \gamma_{3}$ represent frequencies for curves $1, 2$ and $3$ respectively,then

$A$ $5\; W$ source emits monochromatic light of wavelength $5000\; Å$. When placed $0.5\; m$ away, it liberates photoelectrons from a photosensitive metallic surface. When the source is moved to a distance of $1.0\; m$, the number of photoelectrons liberated will

$A$ photosensitive material is at $9\,m$ to the left of the origin and the source of light is at $7\,m$ to the right of the origin along the $x$-axis. The photosensitive material and the source of light start from rest and move,respectively,with $8\widehat{i}\,m/s$ and $4\widehat{i}\,m/s$. The ratio of intensities at $t = 0$ to $t = 3\,s$ as received by the photosensitive material is: