Photoelectrons from a metal do not come out w | vedclass

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Question

(C) According to the photoelectric effect, when light of a suitable frequency falls on a metal surface, electrons are emitted. However, these electron

Vedclass · Accepted Answer

Electrons in a metal occupy different energy levels, and the work function is the minimum energy required for an electron in the highest level of the conduction band to escape the metal.

Vedclass · Answer

(C) According to the photoelectric effect, when light of a suitable frequency falls on a metal surface, electrons are emitted. However, these electrons do not all emerge with the same kinetic energy. This is because electrons inside the metal occupy different energy levels. The work function $(\Phi)$ is defined as the minimum energy required to remove an electron from the highest occupied energy level (Fermi level) of the metal. Electrons located at deeper energy levels require more energy than the work function to escape the surface. Therefore, when a photon of energy $(h
u)$ is absorbed, the kinetic energy of the emitted electron is given by $K_{max} = h
u - \Phi$ for electrons at the surface, while electrons from deeper levels emerge with less kinetic energy. Thus, option (C) is the most appropriate explanation.

Photoelectrons from a metal do not come out with the same energy. The most appropriate explanation is:

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