Pick out the wrong statement from the followi | vedclass

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(C) The lateral shift is given by $L_{s} = t \frac{\sin(i-r)}{\cos r}$. As the angle of incidence $i$ increases,the lateral shift $L_{s}$ increases. T

Vedclass · Accepted Answer

Normal shift decreases as the value of refractive index increases.

Vedclass · Answer

(C) The lateral shift is given by $L_{s} = t \frac{\sin(i-r)}{\cos r}$. As the angle of incidence $i$ increases,the lateral shift $L_{s}$ increases. Thus,statement $A$ is correct.As the refractive index $\mu$ increases,the angle of refraction $r$ decreases,which leads to an increase in the lateral shift $L_{s}$. Thus,statement $B$ is correct.The normal shift is given by $L_{N} = t(1 - \frac{1}{\mu})$. As the refractive index $\mu$ increases,the term $\frac{1}{\mu}$ decreases,which means $(1 - \frac{1}{\mu})$ increases. Therefore,the normal shift $L_{N}$ increases as the refractive index increases. Thus,statement $C$ is incorrect.Both $L_{s}$ and $L_{N}$ are directly proportional to the thickness $t$ of the medium. Thus,statement $D$ is correct.Therefore,the wrong statement is $C$.

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