Point D is 14 ,m towards the West of point A. | vedclass

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(C) Let us represent the positions on a coordinate plane,taking point $A$ as $(0, 0).$Point $A = (0, 0).$Point $D$ is $14 \,m$ West of $A$,so $D = (-1

Vedclass · Accepted Answer

$E$

Vedclass · Answer

(C) Let us represent the positions on a coordinate plane,taking point $A$ as $(0, 0).$Point $A = (0, 0).$Point $D$ is $14 \,m$ West of $A$,so $D = (-14, 0).$Point $B$ is $4 \,m$ South of $D$,so $B = (-14, -4).$Point $F$ is $9 \,m$ South of $D$,so $F = (-14, -9).$Point $E$ is $7 \,m$ East of $B$,so $E = (-14 + 7, -4) = (-7, -4).$Point $C$ is $4 \,m$ North of $E$,so $C = (-7, -4 + 4) = (-7, 0).$Point $G$ is $4 \,m$ South of $A$,so $G = (0, -4).$Now,the person starts at $F(-14, -9)$ and walks $5 \,m$ North. The new position is $(-14, -9 + 5) = (-14, -4)$,which is point $B.$From point $B$,the person takes a right turn. Since the person was facing North,a right turn means they are now facing East.Moving East from $B(-14, -4)$ towards $E(-7, -4)$,the person will reach point $E$ first.

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