The polymer (Q) produced in the following seq | vedclass

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(C) $1$. The starting material is cyclohexanone.$2$. Reaction with hydroxylamine $(NH_2OH)$ followed by acid-catalyzed rearrangement (Beckmann rearran

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Nylon $-6$

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(C) $1$. The starting material is cyclohexanone.$2$. Reaction with hydroxylamine $(NH_2OH)$ followed by acid-catalyzed rearrangement (Beckmann rearrangement) using $H_2SO_4$ and heat converts cyclohexanone into caprolactam (intermediate $P$).$3$. Caprolactam,when heated with water at $533-543 \ K$,undergoes ring-opening polymerization to form Nylon $-6$ (polymer $Q$).$4$. Therefore,the correct option is $C$.

The polymer $(Q)$ produced in the following sequence is:
Cyclohexanone $\xrightarrow[{(ii)\,\,{H_2}SO_4\,,\,\Delta }]{{(i)\,\,NH_2 - OH}}\,P\,$ $\xrightarrow[{533\, - \,543\,\,K}]{{{H_2}O}}Q$

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The polymer $(Q)$ produced in the following sequence is:Cyclohexanone $\xrightarrow[{(ii)\,\,{H_2}SO_4\,,\,\Delta }]{{(i)\,\,NH_2 - OH}}\,P\,$ $\xrightarrow[{533\, - \,543\,\,K}]{{{H_2}O}}Q$