The position of a particle in a rectangular coordinate system is $(3, 2, 5)$. Then its position vector will be
- A$3\hat{i} + 5\hat{j} + 2\hat{k}$
- B$3\hat{i} + 2\hat{j} + 5\hat{k}$
- C$5\hat{i} + 3\hat{j} + 2\hat{k}$
- DNone of these
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Similar Questions
For the components of a vector $\vec{A} = (3 \hat{i} + 4 \hat{j} - 5 \hat{k})$,match the following columns.
Column $I$ Column $II$ $(A)$ Component along $x$-axis $(p)$ $5 \text{ unit}$ $(B)$ Component along vector $(2 \hat{i} + \hat{j} + 2 \hat{k})$ $(q)$ $4 \text{ unit}$ $(C)$ Component along $(6 \hat{i} + 8 \hat{j} - 10 \hat{k})$ $(r)$ $0$ $(D)$ Component along $(-3 \hat{i} - 4 \hat{j} + 5 \hat{k})$ $(s)$ None
| Column $I$ | Column $II$ |
|---|---|
| $(A)$ Component along $x$-axis | $(p)$ $5 \text{ unit}$ |
| $(B)$ Component along vector $(2 \hat{i} + \hat{j} + 2 \hat{k})$ | $(q)$ $4 \text{ unit}$ |
| $(C)$ Component along $(6 \hat{i} + 8 \hat{j} - 10 \hat{k})$ | $(r)$ $0$ |
| $(D)$ Component along $(-3 \hat{i} - 4 \hat{j} + 5 \hat{k})$ | $(s)$ None |
Medium
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Medium
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