Potassium chlorate is prepared by electrolysi | vedclass

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Question

(A) The balanced equation is:$6 OH^{-} + Cl^{-} \rightarrow ClO_{3}^{-} + 3 H_{2}O + 6 e^{-}$From the stoichiometry,$1 \ mol$ of $KClO_{3}$ is produce

Vedclass · Accepted Answer

$1$

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(A) The balanced equation is:$6 OH^{-} + Cl^{-} ightarrow ClO_{3}^{-} + 3 H_{2}O + 6 e^{-}$From the stoichiometry,$1 \ mol$ of $KClO_{3}$ is produced by the transfer of $6 \ mol$ of electrons ($6 \ F$ charge).Moles of $KClO_{3}$ produced $= \frac{10.0 \ g}{122.6 \ g \ mol^{-1}} \approx 0.08157 \ mol$.Total charge required $Q = n 	imes F = 0.08157 	imes 6 	imes 96500 \ C \approx 47228.5 \ C$.We know $Q = I 	imes t$,where $t = 10 \ h = 10 	imes 3600 \ s = 36000 \ s$.$x = \frac{Q}{t} = \frac{47228.5}{36000} \approx 1.31 \ A$.The nearest integer value of $x$ is $1$.

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