Predict the products formed when cyclohexanecarbaldehyde reacts with the following reagents:
$(i)$ $PhMgBr$ and then $H_3O^{+}$
$(ii)$ Tollens' reagent
$(iii)$ Semicarbazide and weak acid
$(iv)$ Excess ethanol and acid
$(v)$ Zinc amalgam and dilute hydrochloric acid

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) $(i)$ Cyclohexanecarbaldehyde reacts with $PhMgBr$ (a Grignard reagent) followed by acid hydrolysis to form cyclohexylphenylcarbinol.
$(ii)$ Cyclohexanecarbaldehyde reacts with Tollens' reagent $([Ag(NH_3)_2]^+)$ to form the cyclohexanecarboxylate ion and a silver mirror ($Ag$ precipitate).
$(iii)$ Cyclohexanecarbaldehyde reacts with semicarbazide in the presence of a weak acid to form cyclohexanecarbaldehyde semicarbazone.
$(iv)$ Cyclohexanecarbaldehyde reacts with excess ethanol in the presence of dry $HCl$ gas to form cyclohexanecarbaldehyde diethyl acetal.
$(v)$ Cyclohexanecarbaldehyde undergoes Clemmensen reduction with zinc amalgam $(Zn-Hg)$ and dilute hydrochloric acid $(HCl)$ to form methylcyclohexane.

Explore More

Similar Questions

What is the percentage of formaldehyde in formalin (in $\%$)?

Which of the following reagents would carry out the following transformation?
$C_6H_5COCH_3 \rightarrow C_6H_5CH(OD)CH_3$ (Note: The product shows a deuterium atom attached to the chiral carbon,not the oxygen).

Which of the following does not give alcohol with $NaBH_4$?

In the given reaction,what is $Y$?
$(P)$ $\xrightarrow{\Delta} X$ $\xrightarrow{Zn-Hg/HCl} Y$

What is the main product obtained by the cross-aldol condensation of benzene carbaldehyde and $1$-phenyl ethane$-1$-one?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo