Pressure is determined as force per unit area of the surface. The $SI$ unit of pressure, Pascal is as shown below:
$1 \, Pa = 1 \, N \, m^{-2}$
If mass of air at sea level is $1034 \, g \, cm^{-2}$, calculate the pressure in Pascal.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
Pressure is defined as force acting per unit area of the surface.
$P = \frac{F}{A}$
Force $(F)$ = $mass \times acceleration \, due \, to \, gravity = 1034 \, g \, cm^{-2} \times 9.8 \, m \, s^{-2}$
Convert units to $SI$ $(kg, m, s)$:
$F = 1034 \, g \times (10^{-3} \, kg / 1 \, g) \times 9.8 \, m \, s^{-2} = 1.034 \, kg \times 9.8 \, m \, s^{-2} = 10.1332 \, N$
Area $(A)$ = $1 \, cm^{2} = (10^{-2} \, m)^{2} = 10^{-4} \, m^{2}$
Pressure $(P)$ = $\frac{F}{A} = \frac{10.1332 \, N}{10^{-4} \, m^{2}} = 1.01332 \times 10^{5} \, N \, m^{-2}$
Since $1 \, Pa = 1 \, N \, m^{-2}$, the pressure is $1.01332 \times 10^{5} \, Pa$.

Explore More

Similar Questions

According to the significant figure convention, the result obtained by adding $12.11$, $18.0$, and $1.012$ is:

Round up the following up to three significant figures:
$(i) 34.216$
$(ii) 10.4107$
$(iii) 0.04597$
$(iv) 2808$

If an object weighs $275 \ lb$,what is its weight in $kg$? $(1 \ kg = 2.205 \ lb)$

Difficult
View Solution

How many significant figures are present in $7.964 \times 10^{3}$?

The triple point of water is $................$ $K$. (in $.16$)

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo