Pressure of an ideal gas is increased by keep | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The average kinetic energy $(KE)$ of an ideal gas molecule is given by the formula: $KE = \frac{3}{2} k_B T$,where $k_B$ is the Boltzmann constant

Vedclass · Accepted Answer

No change

Vedclass · Answer

(C) The average kinetic energy $(KE)$ of an ideal gas molecule is given by the formula: $KE = \frac{3}{2} k_B T$,where $k_B$ is the Boltzmann constant and $T$ is the absolute temperature.Since the temperature $(T)$ is kept constant,the average kinetic energy $(KE)$ of the gas molecules remains constant.Even though the pressure is increased (which implies a decrease in volume for a fixed amount of gas according to Boyle's Law,$PV = 	ext{constant}$),the kinetic energy depends solely on the temperature.Therefore,there is no change in the kinetic energy of the molecules.

Pressure of an ideal gas is increased by keeping temperature constant. What is the effect on the kinetic energy of molecules?

Similar Questions

Write the kinetic interpretation of temperature.

If $E$ is the kinetic energy per mole of an ideal gas and $T$ is the absolute temperature,then the universal gas constant is given as

In the case of hydrogen and oxygen at $N.T.P.$,which of the following quantities is/are the same?

Molecular motion shows itself as

$A$ gas is contained in a vessel at pressure $P_0$. If the mass of all molecules is halved and their speed is doubled,what will be the final pressure?

Vedclass Test Series

Exam Paper Generator

Online Exam Module