Primary side of a transformer is connected to $230 \ V, 50 \ Hz$ supply. The turns ratio of primary to secondary winding is $10:1$. The load resistance connected to the secondary side is $46 \ \Omega$. The power consumed in it is: (in $W$)

An $AC$ source of internal resistance $10^3 \Omega$ is connected to a transformer. The ratio of the number of turns in the primary to the number of turns in the secondary to match the source to a load resistance of $10 \Omega$ is

If a step-up transformer has a turn ratio of $5$,a frequency of $50 \, Hz$,the root mean square $(RMS)$ value of the potential difference on the primary is $100 \, V$,and the resistance of the secondary winding is $500 \, \Omega$,then the peak value of the voltage in the secondary winding will be (the efficiency of the transformer is $100 \%$).

The core of a transformer is made up of:

$A$ current of $5 \,A$ is flowing at $220 \,V$ in the primary coil of a transformer. If the voltage produced in the secondary coil is $2200 \,V$ and $50 \%$ of power is lost, then the current in the secondary will be (in $A$)

$A$ step-up transformer operates on a $220 \,V$ line and supplies $2.2 \,A$. The ratio of primary to secondary winding turns is $11:50$. The output voltage in the secondary is .......... $V$.