The principal organic product of the reaction | vedclass

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(B) The reaction proceeds via an $S_{N}2$ mechanism. In an $S_{N}2$ reaction,the nucleophile $(PhS^-)$ attacks the chiral carbon from the side opposit

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(B) The reaction proceeds via an $S_{N}2$ mechanism. In an $S_{N}2$ reaction,the nucleophile $(PhS^-)$ attacks the chiral carbon from the side opposite to the leaving group $(Cl^-)$. This results in an inversion of configuration at the reaction center (Walden inversion). Comparing the starting material with the options,option $(B)$ shows the correct stereochemical inversion where the $PhS$ group is placed on the side opposite to where the $Cl$ was originally located.

The principal organic product of the reaction will be:

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Consider the above chemical reaction. Product $A$ is:

Which of the following will undergo $S_{N}2$ reaction most rapidly?

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