Identify the product C in the following react | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Step $1$: Benzoic acid $(C_6H_5COOH)$ reacts with $NH_3$ followed by heating to form benzamide $(C_6H_5CONH_2)$,which is product $A$.Step $2$: Ben

Vedclass · Accepted Answer

Phenyl isocyanide $(C_6H_5NC)$

Vedclass · Answer

(D) Step $1$: Benzoic acid $(C_6H_5COOH)$ reacts with $NH_3$ followed by heating to form benzamide $(C_6H_5CONH_2)$,which is product $A$.Step $2$: Benzamide $(C_6H_5CONH_2)$ undergoes the Hofmann bromamide degradation reaction with $Br_2$ and $KOH$ to form aniline $(C_6H_5NH_2)$,which is product $B$.Step $3$: Aniline $(C_6H_5NH_2)$ reacts with $CHCl_3$ and $KOH$ (carbylamine reaction) to form phenyl isocyanide $(C_6H_5NC)$,which is product $C$.

Identify the product $C$ in the following reaction sequence:
$C_6H_5COOH$ $\xrightarrow{NH_3, \Delta} A$ $\xrightarrow{Br_2, KOH} B$ $\xrightarrow{CHCl_3, KOH} C$

Similar Questions

Azo-dyes are prepared from:

The action of nitrous acid on ethyl amine gives

What will be the structure of product $T$ in the following reaction?

The product $(A)$ is:

Which one of the following compounds forms a quaternary salt on reacting with excess methyl iodide?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Identify the product $C$ in the following reaction sequence:$C_6H_5COOH$ $\xrightarrow{NH_3, \Delta} A$ $\xrightarrow{Br_2, KOH} B$ $\xrightarrow{CHCl_3, KOH} C$