The reaction is given as follows:Ph-CO-N(CH_3 | vedclass

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(B) The starting material is $N$-methoxy-$N$-methylbenzamide (Weinreb amide).Weinreb amides react with Grignard reagents $(RMgX)$ to form ketones afte

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$Ph-CO-CH_3$

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(B) The starting material is $N$-methoxy-$N$-methylbenzamide (Weinreb amide).Weinreb amides react with Grignard reagents $(RMgX)$ to form ketones after hydrolysis.In this reaction,$N$-methoxy-$N$-methylbenzamide reacts with $2$ equivalents of $CH_3MgBr$.The first equivalent of $CH_3MgBr$ attacks the carbonyl carbon to form a stable tetrahedral intermediate,which prevents further reaction with the Grignard reagent.Upon acid hydrolysis $(H_3O^+)$,this intermediate decomposes to form acetophenone $(Ph-CO-CH_3)$.Therefore,the product $(P)$ is acetophenone $(Ph-CO-CH_3)$.

The reaction is given as follows:
$Ph-CO-N(CH_3)(OCH_3) + 2CH_3MgBr \xrightarrow{H_3O^+} (P)$
Product $(P)$ is:

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The reaction is given as follows:$Ph-CO-N(CH_3)(OCH_3) + 2CH_3MgBr \xrightarrow{H_3O^+} (P)$Product $(P)$ is: