The product (C) in the following reaction seq | vedclass

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(A) Step $1$: Reaction with $SO_2Cl_2$ in the presence of $h
u$ (light) is a free radical chlorination. It selectively chlorinates the tertiary carbo

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(A) Step $1$: Reaction with $SO_2Cl_2$ in the presence of $h
u$ (light) is a free radical chlorination. It selectively chlorinates the tertiary carbon of the cyclopentyl group attached to the benzene ring to form $(A)$,which is $1-chloro-1-phenylcyclopentane$ derivative.Step $2$: Reaction with $NBS$ ($N$-Bromosuccinimide) is a benzylic bromination. It replaces a hydrogen atom on the methyl group attached to the benzene ring with a bromine atom to form $(B)$,which is $1-chloro-1-(4-(bromomethyl)phenyl)cyclopentane$.Step $3$: Reaction with $KSH$ is a nucleophilic substitution $(S_N2)$ reaction. The $SH^-$ nucleophile attacks the benzylic carbon,replacing the bromine atom to form $(C)$,which is $1-chloro-1-(4-(mercaptomethyl)phenyl)cyclopentane$.

The product $(C)$ in the following reaction sequence is:

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