What are the products (A) and (B) respectivel | vedclass

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(B) For the first reaction,the substrate is $3$-hydroxybenzyl alcohol. The reaction with $HBr$ involves the protonation of the $-OH$ group on the side

Vedclass · Accepted Answer

$3-$hydroxybenzyl bromide and $3-$hydroxyphenol

Vedclass · Answer

(B) For the first reaction,the substrate is $3$-hydroxybenzyl alcohol. The reaction with $HBr$ involves the protonation of the $-OH$ group on the side chain,followed by the loss of water to form a stable benzylic carbocation. This carbocation then reacts with $Br^-$ to form $3$-hydroxybenzyl bromide. This follows an $S_N1$ mechanism.For the second reaction,the substrate is $3$-methoxyphenol. The reaction with $HBr$ involves the protonation of the oxygen atom of the methoxy group. Since the methyl group is attached to the oxygen,the $Br^-$ ion attacks the methyl group,leading to the cleavage of the $C-O$ bond and the formation of $3$-hydroxyphenol (resorcinol) and $CH_3Br$. This follows an $S_N2$ mechanism because the methoxy group is a poor leaving group and the methyl group is sterically unhindered.Therefore,the products are $3$-hydroxybenzyl bromide and $3$-hydroxyphenol.

What are the products $(A)$ and $(B)$ respectively?

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