The products (A) and (B) of the above reactio | vedclass

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(C) The reaction shown is a Cope elimination,which is a concerted $syn$-elimination reaction.In the $syn$-elimination,the $\beta$-hydrogen and the ami

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$A = P, B = Q$

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(C) The reaction shown is a Cope elimination,which is a concerted $syn$-elimination reaction.In the $syn$-elimination,the $\beta$-hydrogen and the amine oxide group must be on the same side (cis) to form a cyclic transition state.For the first substrate (syn-isomer),the $\beta$-hydrogen and the $-NMe_2O^-$ group are on the same side,allowing the formation of product $(P)$ ($3$-phenylcyclohexene).For the second substrate (anti-isomer),the $\beta$-hydrogen and the $-NMe_2O^-$ group are on the same side after rotation,allowing the formation of product $(Q)$ ($1$-phenylcyclohexene),which is more stable due to conjugation with the phenyl ring.Therefore,$(A) = P$ and $(B) = Q$.

The products $(A)$ and $(B)$ of the above reaction are:

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