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(C) The reaction is an intramolecular oxymercuration-demercuration $(OMDM)$ reaction. $1$. The alkene reacts with $Hg(OAc)_2$ to form a cyclic mercuri

Vedclass · Accepted Answer

$2,2-$dimethyltetrahydro-2H-pyran

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(C) The reaction is an intramolecular oxymercuration-demercuration $(OMDM)$ reaction. $1$. The alkene reacts with $Hg(OAc)_2$ to form a cyclic mercurinium ion intermediate. $2$. The internal hydroxyl group $(-OH)$ acts as a nucleophile and attacks the more substituted carbon of the mercurinium ion,leading to ring closure. $3$. The subsequent treatment with $NaBH_4$ replaces the $-HgOAc$ group with a hydrogen atom. $4$. The starting material is $6$-methylhept-$5$-en-$1$-ol. The cyclization forms a six-membered ring containing an oxygen atom (a tetrahydropyran derivative) with two methyl groups at the $2$-position. $5$. The final product is $2,2$-dimethyltetrahydro-$2H$-pyran.

Product $(A)$ of the above reaction is

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