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(A) The reaction starts with the protonation of the hydroxyl group of tetrahydrofurfuryl alcohol,followed by the loss of water to form a primary carbo

Vedclass · Accepted Answer

Tetrahydropyran$-2-$yl ether derivative

Vedclass · Answer

(A) The reaction starts with the protonation of the hydroxyl group of tetrahydrofurfuryl alcohol,followed by the loss of water to form a primary carbocation. This carbocation undergoes ring expansion to form a more stable six-membered oxocarbenium ion. Loss of a proton from this ion yields $3,4-$dihydro-2H-pyran as intermediate $(A)$. Subsequent acid-catalyzed addition of the alcohol $ROH$ to the double bond of $3,4-$dihydro-2H-pyran follows Markovnikov's rule,where the alkoxy group attaches to the carbon adjacent to the oxygen atom,resulting in the formation of a tetrahydropyran$-2-$yl ether derivative as the major product $(B)$.

Product $(B)$ of the above reaction is

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