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(C) The reaction involves the acid-catalyzed dehydration of an alcohol. $1$. Protonation of the $-OH$ group occurs,followed by the loss of a water mol

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(C) The reaction involves the acid-catalyzed dehydration of an alcohol. $1$. Protonation of the $-OH$ group occurs,followed by the loss of a water molecule to form a secondary carbocation. $2$. $A$ methyl shift occurs to rearrange the carbocation into a more stable tertiary carbocation. $3$. The carbocation then undergoes an intramolecular electrophilic attack on the double bond to form a new ring. $4$. Finally,the loss of a proton $(-H^+)$ leads to the formation of the final product,which is a bicyclic alkene.

Product $(A)$ is

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