The product (A) of the reaction is: | vedclass

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(B) The reaction of the given tertiary alcohol with $SOCl_2$ in the presence of pyridine typically proceeds via a carbocation intermediate due to the

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(B) The reaction of the given tertiary alcohol with $SOCl_2$ in the presence of pyridine typically proceeds via a carbocation intermediate due to the steric hindrance and the potential for rearrangement. $1$. The hydroxyl group is converted into a good leaving group (chlorosulfite ester),which then departs to form a carbocation. $2$. The carbocation undergoes a ring expansion (Wagner-Meerwein rearrangement) to relieve ring strain and form a more stable carbocation. $3$. Pyridine,acting as a base,then abstracts a proton from the adjacent carbon to form an alkene as the major product. $4$. Based on the provided reaction mechanism image,the final product $(A)$ is the alkene shown in option $(B)$.

The product $(A)$ of the reaction is:

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