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(B) The reaction is a hydroboration-oxidation of an alkene. Hydroboration-oxidation follows anti-Markovnikov addition of water across the double bond.

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(B) The reaction is a hydroboration-oxidation of an alkene. Hydroboration-oxidation follows anti-Markovnikov addition of water across the double bond. In the given substrate,the double bond is in the five-membered ring. The boron atom attaches to the less hindered carbon atom,which is the carbon further from the benzene ring fusion,to minimize steric hindrance and stabilize the developing partial positive charge in the transition state. Subsequent oxidation with $H_2O_2$ and $HO^-$ replaces the boron group with a hydroxyl $(-OH)$ group,resulting in the formation of the alcohol at the position further from the ring fusion.

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