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(C) The reaction proceeds in two steps:$1$. The starting material is $1$-tetralol. Treatment with $TsCl$ (p-toluenesulfonyl chloride) in the presence

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tetralin ($1$,$2$,$3$,$4$-tetrahydronaphthalene)

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(C) The reaction proceeds in two steps:$1$. The starting material is $1$-tetralol. Treatment with $TsCl$ (p-toluenesulfonyl chloride) in the presence of pyridine converts the hydroxyl group into a good leaving group,the tosylate group $(-OTs)$,forming intermediate $(A)$,which is $1$-tetralyl tosylate.$2$. The subsequent treatment with $LiAlH_4$ (a strong reducing agent) performs a nucleophilic substitution (reduction) of the tosylate group,replacing it with a hydride ion $(H^-)$ to yield tetralin ($1,2,3,4$-tetrahydronaphthalene) as the final product $(B)$.

Product $(B)$ of the above reaction is

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