The product (P) in the given reaction is: | vedclass

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(A) The reaction involves the hydroboration-oxidation of methylenecyclohexane. $(i)$ The first step is the addition of borane $(BH_3)_2$ across the do

Vedclass · Accepted Answer

Cyclohexylmethanol

Vedclass · Answer

(A) The reaction involves the hydroboration-oxidation of methylenecyclohexane. $(i)$ The first step is the addition of borane $(BH_3)_2$ across the double bond,which follows anti-Markovnikov addition. (ii) The second step is the oxidation with $H_2O_2$ in the presence of $OH^-$,which replaces the boron atom with a hydroxyl group $(-OH)$. This process results in the formation of a primary alcohol. Thus,methylenecyclohexane reacts to form cyclohexylmethanol.

The product $(P)$ in the given reaction is:

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