The product (A) of the following reaction is | vedclass

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(C) The reaction involves the $\alpha$-bromination of a ketone. In the presence of a Lewis acid like $AlCl_3$ or an acid catalyst,the ketone exists in

Vedclass · Accepted Answer

$2-$bromo$-1-$phenylbutan$-1-$one

Vedclass · Answer

(C) The reaction involves the $\alpha$-bromination of a ketone. In the presence of a Lewis acid like $AlCl_3$ or an acid catalyst,the ketone exists in equilibrium with its enol form. The enol form acts as a nucleophile and attacks the $Br_2$ molecule. The $\alpha$-carbon (the carbon adjacent to the carbonyl group) is the site of nucleophilic attack. For $1$-phenylbutan-$1$-one $(C_6H_5COCH_2CH_2CH_3)$,the $\alpha$-carbon is the one attached to the carbonyl group $(C_6H_5COCH(Br)CH_2CH_3)$. Therefore,the product is $2$-bromo-$1$-phenylbutan-$1$-one.

The product $(A)$ of the following reaction is (bromination does not occur in the benzene ring):

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