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(B) The starting material is $2(5H)$-furanone. Step $1$: Reduction with $NaBH_4$ selectively reduces the carbonyl group to a hydroxyl group,yielding $

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furan

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(B) The starting material is $2(5H)$-furanone. Step $1$: Reduction with $NaBH_4$ selectively reduces the carbonyl group to a hydroxyl group,yielding $2,5$-dihydrofuran-$2$-ol (compound $(A)$). Step $2$: Acid-catalyzed dehydration $(H^+/\Delta)$ of the cyclic hemiacetal $(A)$ leads to the formation of furan (compound $(B)$) by the elimination of a water molecule and restoration of aromaticity.

The product $(B)$ of the reaction is:

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