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(A) The reaction sequence is as follows:$1$. The starting material is indanone. Reaction with $HCN$ leads to the formation of a cyanohydrin.$2$. Reduc

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(A) The reaction sequence is as follows:$1$. The starting material is indanone. Reaction with $HCN$ leads to the formation of a cyanohydrin.$2$. Reduction of the cyanohydrin with $LiAlH_4$ reduces the $-CN$ group to a $-CH_2NH_2$ group,forming a $\beta$-amino alcohol.$3$. Treatment with $NaNO_2/H^+$ (Tiffeneau-Demjanov rearrangement conditions) leads to the deamination and ring expansion of the five-membered ring to a six-membered ring,resulting in the formation of $\alpha$-tetralone.Thus,the final product $(A)$ is $\alpha$-tetralone.

Product $(A)$ is

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