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(C) The reaction involves the treatment of $1,7-dichloroheptan-4-one$ with $2 	ext{ moles}$ of alcoholic $KOH$. $KOH$ acts as a base and abstracts th

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Dicyclopropyl ketone

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(C) The reaction involves the treatment of $1,7-dichloroheptan-4-one$ with $2 	ext{ moles}$ of alcoholic $KOH$. $KOH$ acts as a base and abstracts the acidic $\alpha$-hydrogen atoms adjacent to the carbonyl group. The resulting enolate ions undergo intramolecular nucleophilic substitution (an example of Neighboring Group Participation or $N$.$G$.$P$.) to form two cyclopropane rings attached to the carbonyl carbon. Thus,the final product $(A)$ is dicyclopropyl ketone.

The product $(A)$ is:

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