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(B) The reaction proceeds in two steps: $1$. Friedel-Crafts acylation of benzene with propanoyl chloride in the presence of $AlCl_3$ yields propiophen

Vedclass · Accepted Answer

Propylbenzene

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(B) The reaction proceeds in two steps: $1$. Friedel-Crafts acylation of benzene with propanoyl chloride in the presence of $AlCl_3$ yields propiophenone as product $(A)$. $C_6H_6 + CH_3CH_2COCl \xrightarrow{AlCl_3} C_6H_5COCH_2CH_3 (A)$ $2$. The Wolff-Kishner reduction of $(A)$ using hydrazine $(NH_2-NH_2)$ and a strong base $(HO^-)$ at high temperature reduces the carbonyl group to a methylene group,yielding propylbenzene as product $(B)$. $C_6H_5COCH_2CH_3 \xrightarrow{NH_2-NH_2, HO^-, \Delta} C_6H_5CH_2CH_2CH_3 (B)$ Thus,the final product $(B)$ is propylbenzene.

Product $(B)$ in this reaction is

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