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(B) $1$. The reaction of $p$-toluidine ($4$-methylaniline) with $NaNO_2/HCl$ at $0-5 \ ^\circ C$ produces $p$-methylbenzenediazonium chloride,which is

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(B) $1$. The reaction of $p$-toluidine ($4$-methylaniline) with $NaNO_2/HCl$ at $0-5 \ ^\circ C$ produces $p$-methylbenzenediazonium chloride,which is intermediate $(A)$.$2$. This diazonium salt undergoes an electrophilic aromatic substitution (coupling reaction) with phenol in a mild basic medium.$3$. The diazonium cation acts as an electrophile and attacks the electron-rich ring of phenol.$4$. Since the para position of phenol is less sterically hindered than the ortho position,the coupling occurs primarily at the para position to form $4$-hydroxy-$4'$-methylazobenzene as the major product $(B)$.

Product $(B)$ of this reaction is

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