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(B) The reaction proceeds in two steps:$1$. The first step is a nucleophilic aromatic substitution $(S_NAr)$ reaction where $1-chloro-4-nitrobenzene$

Vedclass · Accepted Answer

$4-$(dimethylamino)aniline

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(B) The reaction proceeds in two steps:$1$. The first step is a nucleophilic aromatic substitution $(S_NAr)$ reaction where $1-chloro-4-nitrobenzene$ reacts with dimethylamine $(CH_3-NH-CH_3)$. The dimethylamino group replaces the chlorine atom at the para position,forming $N,N-dimethyl-4-nitroaniline$ as product $(A)$.$2$. The second step is the reduction of the nitro group $(-NO_2)$ to an amino group $(-NH_2)$ using $Fe/HCl$. This converts $N,N-dimethyl-4-nitroaniline$ into $N,N-dimethyl-p-phenylenediamine$ (also known as $4-(dimethylamino)aniline$) as product $(B)$.

Product $(B)$ of this reaction is:

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