Product '$A$' and '$B$' are respectively:
$CH_3-C(CH_3)=CH-C_6H_5 \xrightarrow{HBr/Peroxide} A$
$CH_3-C(CH_3)=CH-C_6H_5 \xrightarrow{HBr} B$

  • A
    $CH_3-C(Br)(CH_3)-CH_2-C_6H_5$ and $CH_3-CH(CH_3)-CH(Br)-C_6H_5$
  • B
    $CH_3-CH(CH_3)-CH(Br)-C_6H_5$ and $CH_3-C(Br)(CH_3)-CH_2-C_6H_5$
  • C
    Both are $CH_3-C(Br)(CH_3)-CH_2-C_6H_5$
  • D
    Both are $CH_3-CH(CH_3)-CH(Br)-C_6H_5$

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