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(B) The reaction of a ketoxime with an acid catalyst like $H_2SO_4$ is known as the $	ext{Beckmann rearrangement}$.
In this reaction,the group anti

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(B) The reaction of a ketoxime with an acid catalyst like $H_2SO_4$ is known as the $	ext{Beckmann rearrangement}$.
In this reaction,the group anti to the hydroxyl $(-OH)$ group on the nitrogen atom migrates to the nitrogen,followed by the addition of water and tautomerization to form an amide.
The starting material is a ketoxime. Upon treatment with $H_2SO_4$,the $-OH$ group is protonated and leaves as water,creating a nitrenium ion intermediate. The alkyl group (decalin ring) migrates to the nitrogen,and subsequent attack by water followed by tautomerization yields the corresponding amide,$N$-(decalin$-1-$yl)acetamide.
Therefore,the correct product and reaction name are $N$-(decalin$-1-$yl)acetamide and $	ext{Beckmann rearrangement}$ respectively.

Column-$I$	Column-$II$
$(i)$ Substitution reaction	$(p)$ $CH_2=CH_2 + Br_2 \to CH_2Br-CH_2Br$
$(ii)$ Addition reaction	$(q)$ $C_6H_6 + NO_2^+ \to C_6H_5NO_2 + H^+$
$(iii)$ Electrophilic addition reaction	$(r)$ $CH_3Cl + NaOH \to CH_3OH + NaCl$
$(iv)$ Electrophilic substitution reaction	$(s)$ $CH_3CH_2OH \xrightarrow[\Delta]{Al_2O_3} CH_2=CH_2$
$(v)$ Elimination reaction

Identify the product and the name of the reaction for the following transformation:
$
\begin{array}{c}
\text{Decalin-1-one oxime} \rightarrow{H_2SO_4} \text{Product}
\end{array} $
(The starting material is a ketoxime derived from decalin$-1-$one with a methyl group at the alpha position).

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Identify the product and the name of the reaction for the following transformation: $ \begin{array}{c} \text{Decalin-1-one oxime} \rightarrow{H_2SO_4} \text{Product} \end{array} $ (The starting material is a ketoxime derived from decalin$-1-$one with a methyl group at the alpha position).