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(D) The reaction of benzene $(C_6H_6)$ with ethene $(CH_2=CH_2)$ in the presence of $HCl$ and $AlCl_3$ is a Friedel-Crafts alkylation reaction.First,$

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Ethylbenzene

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(D) The reaction of benzene $(C_6H_6)$ with ethene $(CH_2=CH_2)$ in the presence of $HCl$ and $AlCl_3$ is a Friedel-Crafts alkylation reaction.First,$CH_2=CH_2$ reacts with $HCl$ in the presence of $AlCl_3$ to form an ethyl carbocation $(CH_3CH_2^+)$ or an activated complex that acts as an electrophile.This electrophile then attacks the benzene ring to form ethylbenzene $(C_6H_5CH_2CH_3)$.Therefore,the correct product is ethylbenzene.

What is the product of the following reaction?
$C_6H_6 + CH_2=CH_2 \xrightarrow{HCl, AlCl_3} \text{Product}$

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What is the product of the following reaction?$C_6H_6 + CH_2=CH_2 \xrightarrow{HCl, AlCl_3} \text{Product}$