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Given below are two statements: Consider the following reaction: $R_2C=O + H_2O \rightleftharpoons R_2C(OH)_2$.
Statement $I$: In the case of formaldehyde $(HCHO)$,$K_{eq}$ is about $2280$,due to small substituents,hydration is faster.
Statement $II$: In the case of trichloroacetaldehyde $(CCl_3CHO)$,$K_{eq}$ is about $2000$ due to the $-I$ effect of $-Cl$ atoms.
In the light of the above statements,choose the correct answer from the options given below:

When an aldehyde is treated with an excess of monohydric alcohol,what is formed?

Match List-$I$ with List-$II$.
List-$I$ (Reactions)List-$II$ (Reagents)
$(A)$ $CH_3(CH_2)_5COOC_2H_5 \rightarrow CH_3(CH_2)_5CHO$$(I)$ $CH_3MgBr, H_2O$
$(B)$ $C_6H_5COC_6H_5 \rightarrow C_6H_5CH_2C_6H_5$$(II)$ $Zn(Hg)$ and conc. $HCl$
$(C)$ $C_6H_5CHO \rightarrow C_6H_5CH(OH)CH_3$$(III)$ $NaBH_4, H^+$
$(D)$ $CH_3COCH_2COOC_2H_5 \rightarrow CH_3CH(OH)CH_2COOC_2H_5$$(IV)$ $DIBAL-H, H_2O$

Choose the correct answer from the options given below:

Benzaldehyde on heating with acetone in the presence of $NaOH$ gives:

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Which of the following statements is false?

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