What is the product of the real roots of the equation ${t^2}{x^2} + |x| + 9 = 0$?

  • A
    Is always positive
  • B
    Is always negative
  • C
    Does not exist
  • D
    None of these

Explore More

Similar Questions

The equation $4^{(x^2 + 2)} - 9 \cdot 2^{(x^2 + 2)} + 8 = 0$ has the solution:

Difficult
View Solution

Solve $\sqrt{5} x^{2} + x + \sqrt{5} = 0$.

Find the remainder when $x^4-11x^3+44x^2-76x+48$ is divided by $x^2-7x+12$.

If $-1$ is a twice repeated root of the equation $a(x^3+x^2)+bx+c=0$,then $a:b:c=$

Let $f(x) = (x - a)(x - b) - (\frac{a + b}{2})$. If $f(x) = 0$ has both non-negative roots,then the minimum value of $f(x)$ is:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo