What is the product of the following reaction | vedclass

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(C) The reaction of an alkene with $OsO_4$ followed by $NaHSO_3$ is a syn-dihydroxylation reaction.This process adds two hydroxyl $(-OH)$ groups to th

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$C$

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(C) The reaction of an alkene with $OsO_4$ followed by $NaHSO_3$ is a syn-dihydroxylation reaction.This process adds two hydroxyl $(-OH)$ groups to the same side of the double bond,resulting in the formation of a cis-diol.For $1,2-	ext{dimethylcyclopentene}$,the two $-OH$ groups will be added to the same face of the cyclopentane ring,while the two methyl groups will be pushed to the opposite side.Looking at the options,option $C$ represents the correct stereochemistry where both $-OH$ groups are on the same side (cis) and both $-CH_3$ groups are on the same side (cis).

What is the product of the following reaction?
$1,2-\text{dimethylcyclopentene} \xrightarrow[2. NaHSO_3]{1. OsO_4} \text{Product}$

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What is the product of the following reaction?$1,2-\text{dimethylcyclopentene} \xrightarrow[2. NaHSO_3]{1. OsO_4} \text{Product}$