Predict the major product of the following reaction:

  • A
    $4-$methylacetanilide with a bromine atom at the ortho position relative to the acetamido group.
  • B
    $N$-($4$-methylphenyl)$-2-$bromoacetamide.
  • C
    $4-$methyl$-2-$(bromomethyl)acetanilide.
  • D
    $2-$bromo$-4-$methylacetanilide.

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Given below are two statements: one is labelled as Assertion $(A)$ and the other is labelled as Reason $(R)$.
Assertion $(A)$: Experimental reaction of $CH_{3}Cl$ with aniline and anhydrous $AlCl_{3}$ does not give $o-$ and $p-$methylaniline.
Reason $(R)$: The $-NH_{2}$ group of aniline becomes deactivating because of salt formation with anhydrous $AlCl_{3}$ and hence yields $m-$methylaniline as the product.
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