Propanoic acid undergoes the HVZ reaction to | vedclass

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Question

(C) The $HVZ$ (Hell-Volhard-Zelinsky) reaction of propanoic acid $(CH_3CH_2COOH)$ with $Cl_2/P$ yields $2-$chloropropanoic acid $(CH_3CHClCOOH)$.In $2

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a stronger acid than propanoic acid

Vedclass · Answer

(C) The $HVZ$ (Hell-Volhard-Zelinsky) reaction of propanoic acid $(CH_3CH_2COOH)$ with $Cl_2/P$ yields $2-$chloropropanoic acid $(CH_3CHClCOOH)$.In $2-$chloropropanoic acid,the chlorine atom is an electron-withdrawing group ($-I$ effect).Electron-withdrawing groups stabilize the carboxylate anion $(RCOO^-)$ by dispersing the negative charge,thereby increasing the acidity of the carboxylic acid.Therefore,$2-$chloropropanoic acid is a stronger acid than propanoic acid.

Propanoic acid undergoes the $HVZ$ reaction to give $2-$chloropropanoic acid. The product obtained is:

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