Propyne was subjected to a reaction with HgSO | vedclass

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(D) When propyne is treated with $dil. H_2SO_4$ in the presence of $HgSO_4$,the major product $P$ is acetone $(CH_3COCH_3)$.This reaction involves the

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$C_6H_{10}O$

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(D) When propyne is treated with $dil. H_2SO_4$ in the presence of $HgSO_4$,the major product $P$ is acetone $(CH_3COCH_3)$.This reaction involves the addition of water to the triple bond to form an enol,which then tautomerizes to the keto form:$CH_3C \equiv CH$ $\xrightarrow{HgSO_4, H_2SO_4} CH_3C(OH)=CH_2$ $\rightarrow CH_3COCH_3$ $(P)$Acetone undergoes an aldol condensation reaction in the presence of $Ba(OH)_2$ to form diacetone alcohol:$2CH_3COCH_3 \xrightarrow{Ba(OH)_2} (CH_3)_2C(OH)CH_2COCH_3$Upon heating,diacetone alcohol undergoes dehydration to form mesityl oxide $(Q)$:$(CH_3)_2C(OH)CH_2COCH_3 \xrightarrow{\Delta} (CH_3)_2C=CHCOCH_3$ $(Q)$The molecular formula of mesityl oxide $(Q)$ is $C_6H_{10}O$.

Propyne was subjected to a reaction with $HgSO_4/dil. H_2SO_4$,which resulted in a product $P$. The product $P$ was heated with $Ba(OH)_2$ to give the product $Q$. The molecular formula of the product $Q$ is

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