Prove that the function defined by $f(x) = \tan x$ is a continuous function.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The function $f(x) = \tan x = \frac{\sin x}{\cos x}$ is defined for all real numbers $x$ such that $\cos x \neq 0$,which means $x \neq (2n + 1) \frac{\pi}{2}$ for any integer $n$.
We know that both the sine function $g(x) = \sin x$ and the cosine function $h(x) = \cos x$ are continuous for all real numbers.
According to the algebra of continuous functions,if $g(x)$ and $h(x)$ are continuous functions,then their quotient $\frac{g(x)}{h(x)}$ is also continuous at all points where the denominator $h(x) \neq 0$.
Since $f(x) = \frac{\sin x}{\cos x}$ is the quotient of two continuous functions and is defined for all $x \in \mathbb{R} \setminus \{(2n + 1) \frac{\pi}{2} : n \in \mathbb{Z}\}$,it follows that $f(x) = \tan x$ is a continuous function on its entire domain.

Explore More

Similar Questions

If $f(x) = \begin{cases} x - 1, & x < 0 \\ \frac{1}{4}, & x = 0 \\ x^2, & x > 0 \end{cases}$,then

If $f(x) = \begin{cases} x, & x > 1 \\ x^2, & x < 1 \end{cases}$,then $\lim_{x \to 1} f(x) = $

If $f:(-7,7) \rightarrow R$ is defined by $f(x)=[x]$ for all $x \in (-7,7)$,then the number of discontinuities of $f$ is

If $f(x) = \begin{cases} 1 + x, & \text{when } x \le 2 \\ 5 - x, & \text{when } x > 2 \end{cases}$,then which of the following is true?

If $f(x)$ is continuous at $x = 3$ where $f(x) = \begin{cases} ax + 1, & \text{for } x \leq 3 \\ bx + 3, & \text{for } x > 3 \end{cases}$,then

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo