Rajesh sells a tape recorder to Mihir at a lo | vedclass

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(B) Let the cost price for Rajesh be $x$.Rajesh sells it to Mihir at a loss of $10 \%$,so the selling price for Rajesh (which is the cost price for Mi

Vedclass · Accepted Answer

$2000$

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(B) Let the cost price for Rajesh be $x$.Rajesh sells it to Mihir at a loss of $10 \%$,so the selling price for Rajesh (which is the cost price for Mihir) is $x 	imes (1 - 0.10) = 0.9x$.Mihir sells it to Shiv at a loss of $20 \%$,so the selling price for Mihir (which is the cost price for Shiv) is $0.9x 	imes (1 - 0.20) = 0.9x 	imes 0.8 = 0.72x$.Given that Shiv pays $Rs. 1440$,we have the equation: $0.72x = 1440$.Solving for $x$: $x = \frac{1440}{0.72} = \frac{144000}{72} = 2000$.Therefore,Rajesh bought the tape recorder for $Rs. 2000$.

Rajesh sells a tape recorder to Mihir at a loss of $10 \%$,and Mihir sells it to Shiv at a loss of $20 \%$. If Shiv pays $Rs. 1440$ for it,at what price did Rajesh buy it? (in $Rs.$)

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