Ramesh takes twice as much time as Mahesh and | vedclass

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(A) Let the time taken by Ramesh to complete the work be $x$ days.Since Ramesh takes twice as much time as Mahesh,Mahesh takes $x/2$ days.Since Ramesh

Vedclass · Accepted Answer

$24, 12$ and $8$

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(A) Let the time taken by Ramesh to complete the work be $x$ days.Since Ramesh takes twice as much time as Mahesh,Mahesh takes $x/2$ days.Since Ramesh takes thrice as much time as Suresh,Suresh takes $x/3$ days.The work done by Ramesh in $1$ day is $1/x$.The work done by Mahesh in $1$ day is $2/x$.The work done by Suresh in $1$ day is $3/x$.Together,they complete the work in $4$ days,so their combined $1$-day work is $1/4$.Therefore,$1/x + 2/x + 3/x = 1/4$.$6/x = 1/4$.$x = 24$.Thus,Ramesh takes $24$ days,Mahesh takes $24/2 = 12$ days,and Suresh takes $24/3 = 8$ days.

Ramesh takes twice as much time as Mahesh and thrice as much time as Suresh to complete a job. If working together,they can complete the job in $4 \, \text{days}$,then the time taken by each of them separately to complete the work is (in $\text{days}$)

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