Rank the following groups in order of R, S pr | vedclass

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(A) To determine the priority,we look at the atoms attached to the chiral center:$1$. Compare the first atom: All are $C$ atoms.$2$. Compare the next

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$C > B > A > D$

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(A) To determine the priority,we look at the atoms attached to the chiral center:$1$. Compare the first atom: All are $C$ atoms.$2$. Compare the next set of atoms attached to these $C$ atoms:- $-CH_2Br$: $C$ is attached to $(Br, H, H)$.- $-CH_2CH_2Br$: $C$ is attached to $(C, H, H)$.- $-CH(CH_3)_2$: $C$ is attached to $(C, C, H)$.- $-C(CH_3)_3$: $C$ is attached to $(C, C, C)$.$3$. Comparing the atomic number of the first point of difference: $Br$ $(35)$ has the highest atomic number,so $-CH_2Br$ is priority $1$.$4$. Next,compare the remaining groups. $-CH_2CH_2Br$ has $C$ attached to $(C, H, H)$,while $-CH(CH_3)_2$ has $C$ attached to $(C, C, H)$. Since $(C, C, H)$ has higher priority than $(C, H, H)$,$-CH(CH_3)_2$ is priority $2$,$-CH_2CH_2Br$ is priority $3$,and $-C(CH_3)_3$ is priority $4$.Thus,the order is $C > A > B > D$.

Rank the following groups in order of $R, S$ priority (Cahn-Ingold-Prelog priority rules,where $1$ is highest priority):
$A) -CH(CH_3)_2$
$B) -CH_2CH_2Br$
$C) -CH_2Br$
$D) -C(CH_3)_3$

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Rank the following groups in order of $R, S$ priority (Cahn-Ingold-Prelog priority rules,where $1$ is highest priority):$A) -CH(CH_3)_2$$B) -CH_2CH_2Br$$C) -CH_2Br$$D) -C(CH_3)_3$