Rationalise the denominator of the following: | vedclass

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(C) To rationalise the denominator,multiply the numerator and the denominator by the conjugate of the denominator,which is $(\sqrt{5}+\sqrt{3})$.$\fra

Vedclass · Accepted Answer

$9+2 \sqrt{15}$

Vedclass · Answer

(C) To rationalise the denominator,multiply the numerator and the denominator by the conjugate of the denominator,which is $(\sqrt{5}+\sqrt{3})$.$\frac{3 \sqrt{5}+\sqrt{3}}{\sqrt{5}-\sqrt{3}} 	imes \frac{\sqrt{5}+\sqrt{3}}{\sqrt{5}+\sqrt{3}}$$= \frac{3(\sqrt{5})^2 + 3\sqrt{15} + \sqrt{15} + (\sqrt{3})^2}{(\sqrt{5})^2 - (\sqrt{3})^2}$$= \frac{3(5) + 4\sqrt{15} + 3}{5 - 3}$$= \frac{15 + 4\sqrt{15} + 3}{2}$$= \frac{18 + 4\sqrt{15}}{2}$$= \frac{2(9 + 2\sqrt{15})}{2}$$= 9 + 2\sqrt{15}$

Rationalise the denominator of the following:
$\frac{3 \sqrt{5}+\sqrt{3}}{\sqrt{5}-\sqrt{3}}$

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Rationalise the denominator of the following:$\frac{3 \sqrt{5}+\sqrt{3}}{\sqrt{5}-\sqrt{3}}$