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(D) The reaction sequence is as follows:$1$. The final product is ethylbenzene,$Ph-CH_2-CH_3$.$2$. The second step is the Wolff-Kishner reduction $(NH

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both $(b)$ and $(c)$

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(D) The reaction sequence is as follows:$1$. The final product is ethylbenzene,$Ph-CH_2-CH_3$.$2$. The second step is the Wolff-Kishner reduction $(NH_2-NH_2, HO^-, \Delta)$,which reduces a carbonyl group $(C=O)$ to a methylene group $(-CH_2-)$.$3$. Therefore,the intermediate $(B)$ must be acetophenone,$Ph-CO-CH_3$.$4$. The first step is ozonolysis $(O_3)$ of an alkene $(A)$ to form $(B)$.$5$. Ozonolysis of an alkene $R_1R_2C=CR_3R_4$ cleaves the double bond to form two carbonyl compounds.$6$. For the alkene $(A)$ $(C_{16}H_{16})$ to yield two molecules of acetophenone $(Ph-CO-CH_3)$,the structure of $(A)$ must be $Ph-C(CH_3)=C(CH_3)-Ph$.$7$. This alkene can exist as both $cis$ and $trans$ isomers,both of which will produce acetophenone upon ozonolysis.$8$. Thus,both $(b)$ and $(c)$ represent the same chemical structure (cis and trans isomers of $2,3-$diphenylbut$-2-$ene).

Reactant $(A)$ in this reaction is

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