For the reaction 2A + B to text{product},the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The given rate law $\frac{-d[A]}{dt} = k[A]$ indicates a first-order reaction with respect to $A$.For a first-order reaction,the integrated rate e

Vedclass · Accepted Answer

$\frac{[A]_0}{e}$

Vedclass · Answer

(C) The given rate law $\frac{-d[A]}{dt} = k[A]$ indicates a first-order reaction with respect to $A$.For a first-order reaction,the integrated rate equation is $[A] = [A]_0 e^{-kt}$.The half-life $t_{1/2}$ for a first-order reaction is given by $t_{1/2} = \frac{\ln 2}{k}$,which implies $k = \frac{\ln 2}{t_{1/2}}$.Substituting the given time $t = \frac{t_{1/2}}{\ln 2}$ into the rate equation:$[A] = [A]_0 e^{-k 	imes (\frac{t_{1/2}}{\ln 2})}$$[A] = [A]_0 e^{-(\frac{\ln 2}{t_{1/2}}) 	imes (\frac{t_{1/2}}{\ln 2})}$$[A] = [A]_0 e^{-1} = \frac{[A]_0}{e}$.

For the reaction $2A + B \to \text{product}$,the rate law is given by $\frac{-d[A]}{dt} = k[A]$. At a time $t = \frac{t_{1/2}}{\ln 2}$,what is the concentration of the reactant $A$?

Similar Questions

The reaction $A \to P$ follows first order kinetics. The percentage of $A$ left after $3$ half-lives is

Sucrose decomposes in acid solution into glucose and fructose according to the first order rate law,with $t_{1/2} = 3.00 \ h$. What fraction of sample of sucrose remains after $8 \ h$ $?$

Given: $2A \rightarrow B$. The rate constant of the reaction is $K = 10^{-2} \ min^{-1}$. Which statement is correct? $(\ln 2 = 0.7)$

The rate of a first-order reaction is $0.04 \ mol \ L^{-1} \ s^{-1}$ at $10 \ s$ and $0.03 \ mol \ L^{-1} \ s^{-1}$ at $20 \ s$ after the initiation of the reaction. The half-life period of the reaction is ......... $s$. (in $.1$)

$R \rightarrow P$ is a first order reaction. For this reaction,a graph of $\ln [R]$ (on $y$-axis) and time (on $x$-axis) gives a straight line with a negative slope. The intercept on the $y$-axis is equal to ($k =$ rate constant):

Vedclass Test Series

Exam Paper Generator

Online Exam Module