Reaction of but-2-ene with acidic KMnO_4 give | vedclass

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(D) The reaction of but$-2-$ene $(CH_3-CH=CH-CH_3)$ with acidic $KMnO_4$ is an oxidative cleavage reaction.Acidic $KMnO_4$ is a strong oxidizing agent

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$CH_3COOH$

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(D) The reaction of but$-2-$ene $(CH_3-CH=CH-CH_3)$ with acidic $KMnO_4$ is an oxidative cleavage reaction.Acidic $KMnO_4$ is a strong oxidizing agent that breaks the carbon-carbon double bond.Since but$-2-$ene is a symmetrical alkene,the oxidative cleavage of the double bond results in the formation of two molecules of acetic acid $(CH_3COOH)$.The reaction is: $CH_3-CH=CH-CH_3 + [O] \xrightarrow{KMnO_4/H^+} 2CH_3COOH$.

Reaction of but$-2-$ene with acidic $KMnO_4$ gives:

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